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| Another noob needing help.... https://www.open-audit.org/phpBB3/viewtopic.php?f=10&t=3843 |
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| Author: | logun21 [ Sat Nov 06, 2010 12:31 am ] |
| Post subject: | Another noob needing help.... |
Hi all, Got an interesting situation - i have 750 workstations in the inventory but i would like to do a search on what is NOT installed - ie are there any without the antivirus and device control pruducts we use. I may be missing something obvious (i hope am!), i can't see how to do it. Another thing - DropBox is not showing up in the software inventory, even though it is installed and is in Add/Remove programs. How do i get this to report in...? Any assistance would be most welcome - thanks in advance! |
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| Author: | Mark [ Mon Nov 22, 2010 9:43 am ] |
| Post subject: | Re: Another noob needing help.... |
You could try setting up a report with a join such as this (this SQL taken from a report in OAv2) - [code]select system.system_id, system.hostname, sys_sw_software.software_name, sys_sw_software.software_version from system left join sys_sw_software on (system.system_id = sys_sw_software.system_id and system.timestamp = sys_sw_software.timestamp and (software_name like '%virus%' or software_name like '%endpoint%')) join oa_group_sys on (system.system_id = oa_group_sys.system_id and oa_group_sys.group_id = ?) group by hostname order by hostname;[/code] Note the left join... As for DropBox... It should list most programs in the Registry at - My Computer\HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Uninstall If it appears in there, it should show up in Open-AudIT. |
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| Author: | logun21 [ Fri Jan 14, 2011 3:44 am ] |
| Post subject: | Re: Another noob needing help.... |
I have to say that the above didn't really help that much - it refers to tables that are not present (oa_group_sys for example). I needed to get up to speed on some sql language and mapped out what how I could get the end result in simple language I wanted List of PCs without software X not installed So I reasoned that (list of PCs) minus (list of PCs with software X installed) = (list of PCs without software X) I believe the following statement does the job: [code]select system_name from system where system_uuid not in (select software_uuid from software where software_name like '%Sophos%') order by 1 [/code] Is this correct or have I overlooked something or got the wrong end of the stick...? |
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| Author: | logun21 [ Fri Jan 14, 2011 9:47 pm ] |
| Post subject: | Re: Another noob needing help.... |
will the left join section (provided i like the right tables) provide a better validation/link? I used just this statement to get the desired results select system_name from system where system_uuid not in (select software_uuid from software where software_name like '%Sophos%') order by 1; (list of all pc's) - (list of pc's with sophos) = (list of pc's without sopohs) |
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